Integrand size = 24, antiderivative size = 57 \[ \int \frac {(c+d x)^{1+2 n-2 (1+n)}}{(a+b x)^2} \, dx=-\frac {1}{(b c-a d) (a+b x)}-\frac {d \log (a+b x)}{(b c-a d)^2}+\frac {d \log (c+d x)}{(b c-a d)^2} \]
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Time = 0.02 (sec) , antiderivative size = 57, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {7, 46} \[ \int \frac {(c+d x)^{1+2 n-2 (1+n)}}{(a+b x)^2} \, dx=-\frac {1}{(a+b x) (b c-a d)}-\frac {d \log (a+b x)}{(b c-a d)^2}+\frac {d \log (c+d x)}{(b c-a d)^2} \]
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Rule 7
Rule 46
Rubi steps \begin{align*} \text {integral}& = \int \frac {1}{(a+b x)^2 (c+d x)} \, dx \\ & = \int \left (\frac {b}{(b c-a d) (a+b x)^2}-\frac {b d}{(b c-a d)^2 (a+b x)}+\frac {d^2}{(b c-a d)^2 (c+d x)}\right ) \, dx \\ & = -\frac {1}{(b c-a d) (a+b x)}-\frac {d \log (a+b x)}{(b c-a d)^2}+\frac {d \log (c+d x)}{(b c-a d)^2} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 53, normalized size of antiderivative = 0.93 \[ \int \frac {(c+d x)^{1+2 n-2 (1+n)}}{(a+b x)^2} \, dx=\frac {-b c+a d-d (a+b x) \log (a+b x)+d (a+b x) \log (c+d x)}{(b c-a d)^2 (a+b x)} \]
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Time = 0.40 (sec) , antiderivative size = 57, normalized size of antiderivative = 1.00
method | result | size |
default | \(\frac {d \ln \left (d x +c \right )}{\left (a d -b c \right )^{2}}+\frac {1}{\left (a d -b c \right ) \left (b x +a \right )}-\frac {d \ln \left (b x +a \right )}{\left (a d -b c \right )^{2}}\) | \(57\) |
risch | \(\frac {1}{\left (a d -b c \right ) \left (b x +a \right )}-\frac {d \ln \left (b x +a \right )}{a^{2} d^{2}-2 a b c d +b^{2} c^{2}}+\frac {d \ln \left (-d x -c \right )}{a^{2} d^{2}-2 a b c d +b^{2} c^{2}}\) | \(86\) |
norman | \(-\frac {b x}{a \left (a d -b c \right ) \left (b x +a \right )}+\frac {d \ln \left (d x +c \right )}{a^{2} d^{2}-2 a b c d +b^{2} c^{2}}-\frac {d \ln \left (b x +a \right )}{a^{2} d^{2}-2 a b c d +b^{2} c^{2}}\) | \(89\) |
parallelrisch | \(-\frac {\ln \left (b x +a \right ) x a b d -\ln \left (d x +c \right ) x a b d +\ln \left (b x +a \right ) a^{2} d -\ln \left (d x +c \right ) a^{2} d +x a b d -b^{2} c x}{\left (a^{2} d^{2}-2 a b c d +b^{2} c^{2}\right ) \left (b x +a \right ) a}\) | \(95\) |
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Time = 0.22 (sec) , antiderivative size = 93, normalized size of antiderivative = 1.63 \[ \int \frac {(c+d x)^{1+2 n-2 (1+n)}}{(a+b x)^2} \, dx=-\frac {b c - a d + {\left (b d x + a d\right )} \log \left (b x + a\right ) - {\left (b d x + a d\right )} \log \left (d x + c\right )}{a b^{2} c^{2} - 2 \, a^{2} b c d + a^{3} d^{2} + {\left (b^{3} c^{2} - 2 \, a b^{2} c d + a^{2} b d^{2}\right )} x} \]
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Leaf count of result is larger than twice the leaf count of optimal. 233 vs. \(2 (46) = 92\).
Time = 0.36 (sec) , antiderivative size = 233, normalized size of antiderivative = 4.09 \[ \int \frac {(c+d x)^{1+2 n-2 (1+n)}}{(a+b x)^2} \, dx=\frac {d \log {\left (x + \frac {- \frac {a^{3} d^{4}}{\left (a d - b c\right )^{2}} + \frac {3 a^{2} b c d^{3}}{\left (a d - b c\right )^{2}} - \frac {3 a b^{2} c^{2} d^{2}}{\left (a d - b c\right )^{2}} + a d^{2} + \frac {b^{3} c^{3} d}{\left (a d - b c\right )^{2}} + b c d}{2 b d^{2}} \right )}}{\left (a d - b c\right )^{2}} - \frac {d \log {\left (x + \frac {\frac {a^{3} d^{4}}{\left (a d - b c\right )^{2}} - \frac {3 a^{2} b c d^{3}}{\left (a d - b c\right )^{2}} + \frac {3 a b^{2} c^{2} d^{2}}{\left (a d - b c\right )^{2}} + a d^{2} - \frac {b^{3} c^{3} d}{\left (a d - b c\right )^{2}} + b c d}{2 b d^{2}} \right )}}{\left (a d - b c\right )^{2}} + \frac {1}{a^{2} d - a b c + x \left (a b d - b^{2} c\right )} \]
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Time = 0.20 (sec) , antiderivative size = 92, normalized size of antiderivative = 1.61 \[ \int \frac {(c+d x)^{1+2 n-2 (1+n)}}{(a+b x)^2} \, dx=-\frac {d \log \left (b x + a\right )}{b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}} + \frac {d \log \left (d x + c\right )}{b^{2} c^{2} - 2 \, a b c d + a^{2} d^{2}} - \frac {1}{a b c - a^{2} d + {\left (b^{2} c - a b d\right )} x} \]
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Time = 0.27 (sec) , antiderivative size = 78, normalized size of antiderivative = 1.37 \[ \int \frac {(c+d x)^{1+2 n-2 (1+n)}}{(a+b x)^2} \, dx=\frac {b d \log \left ({\left | \frac {b c}{b x + a} - \frac {a d}{b x + a} + d \right |}\right )}{b^{3} c^{2} - 2 \, a b^{2} c d + a^{2} b d^{2}} - \frac {b}{{\left (b^{2} c - a b d\right )} {\left (b x + a\right )}} \]
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Time = 0.58 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.81 \[ \int \frac {(c+d x)^{1+2 n-2 (1+n)}}{(a+b x)^2} \, dx=\frac {1}{\left (a\,d-b\,c\right )\,\left (a+b\,x\right )}-\frac {d\,\ln \left (\frac {a+b\,x}{c+d\,x}\right )}{{\left (a\,d-b\,c\right )}^2} \]
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